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437. Path Sum III
Medium
Given the root of a binary tree and an integer targetSum, return the number of paths where the sum of the values along the path equals targetSum.
The path does not need to start or end at the root or a leaf, but it must go downwards (i.e., traveling only from parent nodes to child nodes).
Example 1:
Input: root = [10,5,-3,3,2,null,11,3,-2,null,1], targetSum = 8
Output: 3
Explanation: The paths that sum to 8 are shown.
Example 2:
Input: root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22
Output: 3
Constraints:
- The number of nodes in the tree is in the range
[0, 1000]. -109 <= Node.val <= 109-1000 <= targetSum <= 1000
Solution
import com_github_leetcode.TreeNode
/*
* Definition for a binary tree node.
* class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {
* var value: Int = _value
* var left: TreeNode = _left
* var right: TreeNode = _right
* }
*/
object Solution {
def pathSum(root: TreeNode, targetSum: Int): Int = {
if (root == null) return 0
pathSum(root.left, targetSum) + pathSum(root.right, targetSum) + dfsPath(root, 0, targetSum)
}
private def dfsPath(root: TreeNode, sum: Long, targetSum: Long): Int = {
if (root == null) return 0
val cumSum = sum + root.value
val counter = if (cumSum == targetSum) 1 else 0
counter + dfsPath(root.left, cumSum, targetSum) + dfsPath(root.right, cumSum, targetSum)
}
}